example:
Design an exchanger to sub-cool condensate from a methanol condenser from 95°C to
40°C. Flow-rate of methanol 100,000 kg/h. Cooling water will be used as the coolant,
with a temperature rise from 25°C to 40°C.
1.
Determine the heat exchanger duty
In this example, since coolant is more corrosive, it is assigned to the tube side.
Specific heat capacity of methanol = 3.926kJ/kg°C
Heat Exchanger Duty
Q = mCp.(AT) =(100000/3600) × 3926 × (95 – 40) =
5998.056 × 10³W = 5998.056kW
2.
Specific heat capacity of water[= 4.2kJ/kg°C
Mass flowrate of cooling water:
mwater= Q/Cp.water (Twater out-Twater.in)= (5998056/4200(40-25))= kg/S 95.21 = 342360 kg/hr
Using 1-2 Shell and Tube Heat Exchanger,
Log Mean Temperature Difference:
see simulation
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